Find all the angles between 0° and 360° which satisfy the equation sec y(1 + tan y) = 6 cosec y.

Solution: y= 63.4, 243.4, 108.4, 288.4

1/cosy (1 + tany) = 6(1/siny)

1 + tany = 6 cosy/siny

1 + tany = 6 coty

tany + tan^{2}y = 6

tany + tan^{2}y – 6 = 0

tany = 2 or tany = -3

1st and 3rd quadrant 2nd and 4th quadrant

y = 63.435, 243.43 y= 108.43, 288.43

y = 63.4, 243.4 y = 108.4, 288.4