Find the value of p and of q for

which {x : x < -3 or x > 4} is the

solution set of the inequality

x^{2} + px > q

(x+3)(x-4) > 0

x^{2} – x – 12 > 0

x^{2} – x > 12

compare with x^{2} + px > q

Therefore p= -1, q = 12

Find the value of p and of q for

which {x : x < -3 or x > 4} is the

solution set of the inequality

x^{2} + px > q

(x+3)(x-4) > 0

x^{2} – x – 12 > 0

x^{2} – x > 12

compare with x^{2} + px > q

Therefore p= -1, q = 12