Quadratic inequalities

Find the value of p and of q for
which {x : x < -3 or x > 4} is the
solution set of the inequality

x2 + px > q

(x+3)(x-4) > 0

x2 – x – 12 > 0

x2 – x > 12

compare with x2 + px > q

Therefore p= -1, q = 12

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