Acquiring equation from linearized form

The diagram below shows a straight line graph where (x-y) is plotted against x2y

Express y in terms of x

Solution: 

gradient, m = 16-4/5-1

                    = 3

Y = 3X + C

sub x=1, y=4

4 = 3(1) + C

Y = 3X + 1——-(1)

sub Y = x-y, X =  x2y into (1)

x-y = 3x2y + 1

x-1 = 3 x2y + y

x-1 = y(3 x2 + 1)

x-1 = (x-1) / (3x2 + 1)

 

 

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